Saturday 1 February 2014

convert your ip decimal into a binary ip and store in 2d array

#include<stdio.h>
#include<math.h>
int main()
{
   printf("enter your ip addr part by part mean your ip addr is has 4 part \n enter 1st then press enter so on\n");
  int e,c,l,z,t,x,v,b,a[4][8];
printf("enter 1st part\n");
  scanf("%d",&z);
printf("enter 2nd part\n");
  scanf("%d",&t);
printf("enter 3rd part\n");
  scanf("%d",&x);
printf("enter last part\n");
  scanf("%d",&v);
  printf("\n so the %d.%d.%d.%d\n the binary of the number is\n",z,t,x,v);
  printf("\n%d=",z);
  for (c = 7; c >= 0; c--){
    l = z >> c;
    if (l & 1){
            a[0][c]=1;
      printf("1");
    }
    else{
            a[0][c]=0;
      printf("0");
    }
  }
  printf("\n");
  printf("\n%d=",t);
  for (c = 7; c >= 0; c--){
    l = t >> c;
    if (l & 1){
            a[1][c]=1;
      printf("1");
    }
    else{
            a[1][c]=0;
      printf("0");
  }
  }
  printf("\n");
  printf("\n%d=",x);
  for (c = 7; c >= 0; c--){

    l = x >> c;
    if (l & 1){
            a[2][c]=1;
      printf("1");
    }
    else{
        a[2][c]=0;
      printf("0");
    }
  }
  printf("\n");
  printf("\n%d=",v);
  for (c = 7; c >= 0; c--){
    l = v >> c;
    if (l & 1){
            a[3][c]=1;
      printf("1");
    }
    else{
            a[3][c]=0;
      printf("0");
    }
  }
  printf("\n");
  printf("the array of ip addrres in  binaary is\n");
  for (c = 7; c >= 0; c--){
    printf("%d",a[0][c]);
  }
  printf("\n");
  for (c = 7; c >= 0; c--){
    printf("%d",a[1][c]);
  }
  printf("\n");
  for (c = 7; c >= 0; c--){
    printf("%d",a[2][c]);
  }
  printf("\n");
  for (c = 7; c >= 0; c--){
    printf("%d",a[3][c]);
  }
  return 0;
}

No comments:

Post a Comment